How high does ice ride above the surface of a glass of water? How do I figure this out? Equation?

Ice has a density of 0.92gm/cm to the 3rd


If an ice cude is 2 cm on a side, how high does it ride above the surface of a glass of water? (1.00gm/cm to the 3rd) ?





This a physics question I can't figure out!How high does ice ride above the surface of a glass of water? How do I figure this out? Equation?
If h' is above the water,and h below the water;such that


h'+h=a(the side of the ice cube),then


F(upwards)=axaxh(1-0.92)xg=


=axaxh'x0.92xg=F(downwards),because they are at equilibirium.So,h'x0.92=h(1-0.92)=0.08h


0.08/0.92=h'/h=8/92 %26amp; h' +h=2,h=11.5h'


12.5h'=2, h'=0.16cm above the waterHow high does ice ride above the surface of a glass of water? How do I figure this out? Equation?
0.92 / 1.00 = 0.92 -%26gt; 92% of the ice cube is below water. So 8% is above the water.





8% of 2cm is 0.16cm, which is the height of the ice cube that's above water.





This assumes that the ice cube is sitting flat. If it's corner up, then the answer is different.