Thursday, December 31, 2009

How can you figure out the molality of HCl when following info is given?

molar mass is 36.5 g


density(g/mL) 1.19


mass % 37.2


molarity 12.1





I have to a do set of these probs, and i hope i can get the help to get started on it...thanks!How can you figure out the molality of HCl when following info is given?
molality is moles solute / kg solvent.





If we assume 1 kg of solution, 372 grams will be HCl (from the mass percentage). The remaining 628 g is water.





372 g / 36.5 g/mol = 10.2 moles





10.2 moles / 0.628 kg = 16.2 m





If you're not given the mass percentage, you can figure it out from the density.How can you figure out the molality of HCl when following info is given?
Molality is defined as moles of solute per kg of solvent.





So assume 1 L of solution:





moles of HCl = 12.1 (molarity = moles/L)


mass of solution = 1000 mL x 1.19 g/mL = 1190 g = 1.19 kg solution.


Mass % HCL = 37.2% ---%26gt; water = 62.8%


62.8% of 1.19 kg = 0.747 kg of water (solvent)





Molality = 12.1 moles/0.747 kg of solvent = 16.2 mole/kg

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