Tuesday, December 15, 2009

What factors would be needed to figure out how far the guy sinks after landing?

http://s223.photobucket.com/albums/dd78/鈥?/a>





How would that be calculated?What factors would be needed to figure out how far the guy sinks after landing?
I have a couple of questions, in the picture the block has not landed, are we solving for just the man, or man and block (once the block has landed)? Also, the illustration seems to imply that the system is in equilibrium before the falling masses land,, this would need to be confirmed, if it is the case, then it means the larger piston must be heavier by more than the differences in area, however we don't really have to know the masses of the pistons, since it the difference can be found if we have the fluid density area and height difference.





';civil_av8r'; got off to a strong start, you'll need to know dimensions, masses (man and maybe block, piston masses wouldn't hurt but not really needed) and density of the fluid.





However I think there are some problems with the equations, the illustration gives no sign that atmospheric pressure would be different between the two cylinders, so it doesn't need to be entered into the calculations.


and while the (mass of the man / area of piston), vs. ((difference in piston masses + mass of block?) / piston2 area), is relevant, you do not need density of fluid * area, just density times the height difference.What factors would be needed to figure out how far the guy sinks after landing?
you need to know the dimensions of each cylinder, the fluid density, the mass of the man, and the mass of the block.





to solve it would be simply a bouyancy problem.





1) set a water line





2) FBD any part of the tube connecting the two and the forces should equal eachother





when he man enters the liquid on his side


Atmospheric Pressure*Area + Weight of the man - density of the fluid*Area*delta(x)*gravity = F





on the other side with the block


Atmospheric Pressure*Area + Weight of the block - density of the fuild*Area*delta(x)*gravity = F





the fluid deflection isn't going to be the same and neither are the Weights





Atm*Area1 + Weight of the Man - density of the fluid*Area1*delta(x1)*gravity = Atm*Area2 + Weight of the Block - density of the fluid*Area2*delta(x2)*gravity

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