A bacterial culture has an initial population of 10,000. If it's population declines to 7000 in 2 hours, what will it be at the end of 4 hours?Can someone show me how to figure this out?
P = Ie^kt
7000 = 10,000e^(2k)
7000/10,000 = e^(2k)
0.7 = e^(2k)
ln (0.7) = 2k
k = -0.178
P = Ie^kt
P = 10,000e^(4 x -0.178)
P = 10,000(.490)
P = 4900Can someone show me how to figure this out?
it is not clear can you pleas show more detail
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